Derivative, Maximum, Minimum of Quadratic Functions

Differentiation is used to analyze the properties such as intervals of increase, decrease, local maximum, local minimum of quadratic functions.

A - Quadratic Function in General form

Quadratic functions in their general form are written as

f(x)=ax2+bx+c

where a, b, and c are real numbers such that a0.

The first derivative of f is given by

f(x)=2ax+b

Let us analyze the sign of f and hence determine any maximum or minimum point and the intervals of increase and decrease. f(x) is positive if

2ax+b>0 which may be written as 2ax>b

We now need to consider two cases and continue solving the inequality above.

case 1: coefficient a>0

We divide both sides of the inequality by 2a and solve it to obtain

x>b2a

We now use a table to analyze the sign of f and whether f is increasing over a given interval.

table of sign for \(a > 0\)

The quadratic function with a>0 has a minimum point at (b/2a,f(b/2a)) and the function is decreasing on the interval (,b/2a) and increasing over the interval (b/2a,+).

case 2: coefficient a<0

We divide both sides of the inequality by 2a but because a is less than 0, we need to change the symbol of inequality

x<b2a

We now analyze the sign of f using the table below

table of sign for \(a < 0\)

The quadratic function with a<0 has a maximum point at (b/2a,f(b/2a)) and the function is increasing on the interval (,b/2a) and decreasing over the interval (b/2a,+).

B - Quadratic Function in Vertex form

Quadratic functions in their vertex form are written as

f(x)=a(xh)2+k

where a, h, and k are real numbers with a0.

The first derivative of f is given by

f(x)=2a(xh)

We analyze the sign of f using a table. f(x) is positive if

a(xh)>0

We need to consider two cases again and continue solving the inequality above.

case 1: coefficient a>0

We divide both sides of the inequality by a and solve the inequality

x>h

The table below is used to analyze the sign of f.

table of sign for \(a > 0\), vertex form

The quadratic function with a>0 has a minimum at the point (h,k) and it is decreasing on the interval (,h) and increasing over the interval (h,+).

case 2: coefficient a<0

We divide both sides of the inequality by a but we need to change the symbol of inequality because a is less than 0.

x<h

We analyze the sign of f using the table below

table of sign for \(a < 0\), vertex form

The quadratic function with a<0 has a maximum point at (h,k) and the function is increasing on the interval (,h) and decreasing over the interval (h,+).

Example 1

Find the extremum (minimum or maximum) of the quadratic function f given by

f(x)=2x28x+1

Solution to Example 1

Example 2

Find the extremum (minimum or maximum) of the quadratic function f given by

f(x)=(x+3)2+1

Solution to Example 2

Exercises on Properties of Quadratic Functions

For each quadratic function below find the extremum (minimum or maximum), the interval of increase and the interval of decrease.

a) f(x)=x2+6x
b) f(x)=x22x+3
c) f(x)=x25
d) f(x)=(x4)2+2
e) f(x)=x2

Answers to Above Exercises

a) minimum at the point (3,9)
decreasing on (,3)
increasing on (3,+)

b) maximum at at the point (1,4)
increasing on the interval (,1)
decreasing on the interval (1,+)

c) minimum at at the point (0,5)
decreasing on the interval(,0)
increasing on the interval (0,+)

d) maximum at (4,2)
increasing on the interval (,4)
decreasing on the interval (4,+)

e) maximum at (0,0)
increasing on the interval (,0)
decreasing on the interval (0,+)

More on applications of differentiation

applications of differentiation