Probability Questions with Step-by-Step Solutions

This tutorial covers how to compute the probability of an event. Let \( S \) be the sample space of an experiment and \( E \) the event of interest. The number of elements in \( S \) is written \( n(S) \), and the number of elements in \( E \) is written \( n(E) \).

Questions and Solutions

Question 1

A die is rolled. Find the probability that an even number is obtained.

Solution

The sample space is \[ S = \{1,2,3,4,5,6\} \] The event “even number” is \[ E = \{2,4,6\} \] Using the classical probability formula, \[ P(E) = \frac{n(E)}{n(S)} = \frac{3}{6} = \frac{1}{2} \]

Question 2

Two coins are tossed. Find the probability that two heads are obtained.

Solution

The sample space is \[ S = \{(H,H),(H,T),(T,H),(T,T)\} \] The event “two heads” is \[ E = \{(H,H)\} \] Hence, \[ P(E) = \frac{1}{4} \]

Question 3

Which of the following cannot be a probability?

Solution

A probability must satisfy \( 0 \le P \le 1 \). Therefore, values a) and c) cannot represent probabilities.

Question 4

Two dice are rolled. Find the probability that the sum is:

Solution

The sample space contains \( 36 \) outcomes.

a) No outcome gives a sum of 1, so \[ P = \frac{0}{36} = 0 \]

b) The outcomes are \( \{(1,3),(2,2),(3,1)\} \), hence \[ P = \frac{3}{36} = \frac{1}{12} \]

c) All outcomes give a sum less than 13, so \[ P = \frac{36}{36} = 1 \]

Question 5

A die is rolled and a coin is tossed. Find the probability that the die shows an odd number and the coin shows a head.

Solution

The sample space has \( 12 \) outcomes. The favorable outcomes are \[ E = \{(1,H),(3,H),(5,H)\} \] Therefore, \[ P(E) = \frac{3}{12} = \frac{1}{4} \]

Question 6

A card is drawn at random from a standard deck. Find the probability of getting the 3 of diamonds.

Solution

There are \( 52 \) cards in the deck.

Sample space of a deck of cards

\[ P(E) = \frac{1}{52} \]

Question 7

Find the probability of drawing a queen from a standard deck.

Solution

There are 4 queens in a deck of 52 cards, so \[ P(E) = \frac{4}{52} = \frac{1}{13} \]

Question 8

A jar contains 3 red, 7 green, and 10 white marbles. What is the probability of drawing a white marble?

Solution
ColorFrequency
Red3
Green7
White10

\[ P(E) = \frac{10}{20} = \frac{1}{2} \]

Question 9

The blood types of 200 people are distributed as follows:

GroupFrequency
A50
B65
O70
AB15
Solution

\[ P(\text{O}) = \frac{70}{200} = 0.35 \]

Exercises

Answers

a) \( \frac{1}{3} \)
b) \( \frac{1}{2} \)
c) \( \frac{1}{9} \)
d) \( \frac{1}{52} \)

More References

Elementary Statistics and Probability
AnalyzeMath Home Page