Make a Sign Table of Polynomials
Questions with Solutions

Master Grade 12 math with this step-by-step guide on creating sign tables for polynomial functions. This resource includes challenging practice questions, detailed solutions, and clear graphical interpretations to help you fully understand polynomial behavior.

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Question 1

Polynomial p is given by p(x)=(x1)2(x3)(x+3) Make a sign table of p and sketch a possible graph for p.

solution

We first find the zeros of the polynomial function p(x). p(x)=(x1)2(x3)(x+3)=0

For p(x)=0, we need to have (x1)2=0or(x3)=0or(x+3)=0 Solve each of the above equations to obtain the zeros of p(x). x=1(with multiplicity 2),x=3,andx=3

c) With the help of the factored form of p(x) and its zeros found above, we now make a table of signs using:

(x1)2 is positive for all x except at x=1

x3>0 for x>3

x+3>0 for x>3


We put each factor in the table and use the rules of multiplication of signs to complete the sign for p as shown below.

table of sign question 3.

We use the zeros of p(x) which graphically are shown as x intercepts, the table of signs and the y intercept (0,3) to complete the graph as shown below. polynomials question 1.

Question 2

f(x) is a polynomial of degree six with a negative leading coefficient k. f has a zero of multiplicity 1 at x=1, a zero of multiplicity 3 at x=1, and a zero of multiplicity 2 at x=3. Make a sign table for the polynomial f.

solution

We first write the factors of polynomial f with their multiplicity.

Zero of multiplicity 1 at x=1 : factor: x+1

Zero of multiplicity 3 at x=1 : factor: (x1)3

Zero of multiplicity 2 at x=3 : factor: (x3)2

Let k (negative) be the leading coefficient of f. Using all the above factors, we write f(x) as

f(x)=k(x+1)(x1)3(x3)2

We first study the sign of the different factors of f.

x+1>0 for x>1

(x1)3>0 for x>1

(x3)2>0 for all x except x=3

Below is shown the table of signs of each factor and of the polynomial f(x) in the bottom row. table of sign question 2.

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